If the vertex of image Q' is located at coordinates (16,8) was dilated by a scale factor of 2, what was the coordinates for the pre-image Q?

(32,16)

Step-by-step explanation:

When you dilate a coordinate by a factor say a, the coordinate of the image are multiplied by this factor to get the coordinate of the pre-image. For example, if the coordinate of the image is (x,y) dilated by a factor of "a", the coordinate of the pre-image will be (ax, ay)

Given the coordinate (16, 8) the coordinate of the pre image of dilated by a factor of 2 is given as;

(2×16, 2×8) = (32, 16)

Hence the coordinates for the pre-image Q is (32,16)

25 questions , because they start with 100.  

350-100=250 .  

. 250/10=25

step-by-step explanation:

first take off 100, then what x 10 = 250? that is your answer. (25)

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )