WILL GIVE BRAINLIEST ANSWER FAST I NEED ASAP Select the correct answer.
Which sequence of transformations proves that shape I is similar to shape II?
A. a 90° counterclockwise rotation about the origin, and then a dilation by a scale factor of 2
B. a reflection across the x-axis, and then a dilation by a scale factor of 3
C. a reflection across the x-axis, and then a dilation by a scale factor of 2
D. a 90° counterclockwise rotation about the origin, and then a dilation by a scale factor of 3

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

believe it or not anna is correct good job anna give me a fist bump there u go gal

d is the only accurate one

step-by-step explanation: