Graph the image of this figure after a dilation with a scale factor of 2 centered at the origin.

The graph of the image is attached below.

Step-by-step explanation:

Let the points of the figure

We need to find the image coordinates after the dilation by a scale factor of 2 centered at the origin.

The rule of dilation by a scale factor of 2 is:

Dilation with scale factor 2, multiply by 2.

(x, y) → (2x,2y)

The coordinates of the vertices of the image according to this rule will be:

(x, y) → (2x,2y)

A(1, -1) → (2(1),2(-1)) = A'(2, -2)

B(3, -1) → (2(3),2(-1)) = B'(6, -2)

C(1, 2) → (2(1),2(2)) = C'(2, 4)

D(3, 2) → (2(3),2(2)) = D'(6, 4)

Therefore, the coordinates of the vertices of the image will be:

The graph of the image is attached below.

rotation point l

step-by-step explanation:

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation: