Suzanna walked two over seven of a mile in two over five of an hour. What is her unit rate in miles per hour? Select one:
a. two sevenths over two fifths = one and two fifths miles per hour
b. two fifths over two sevenths = one and two fifths miles per hour
c. two sevenths over two fifths = five over seven mile per hour
d. two fifths over two sevenths = five over seven mile per hour

PLS HELP BRIANLY ISNT WORKING FOR ME SO I NEED HELP ASAP.

Cody was 165cm tall on the first day of school this year, which was 10% taller than he was on the first day of school last year.

In δabc, m∠acb = 90°, cd ⊥ ab and m∠acd = 45°. find: a find cd, if bc = 3 in

Each of the following data sets has a mean of x = 10. (i) 8 9 10 11 12 (ii) 7 9 10 11 13 (iii) 7 8 10 12 13 (a) without doing any computations, order the data sets according to increasing value of standard deviations. (i), (iii), (ii) (ii), (i), (iii) (iii), (i), (ii) (iii), (ii), (i) (i), (ii), (iii) (ii), (iii), (i) (b) why do you expect the difference in standard deviations between data sets (i) and (ii) to be greater than the difference in standard deviations between data sets (ii) and (iii)? hint: consider how much the data in the respective sets differ from the mean. the data change between data sets (i) and (ii) increased the squared difference îł(x - x)2 by more than data sets (ii) and (iii). the data change between data sets (ii) and (iii) increased the squared difference îł(x - x)2 by more than data sets (i) and (ii). the data change between data sets (i) and (ii) decreased the squared difference îł(x - x)2 by more than data sets (ii) and (iii). none of the above