Find three consecutive positive integers such that the product of the first two is 22 less than 11 times the third. (Type the answers in order - from
lowest to highest) *

10,11,12

Step-by-step explanation:

1st integer= x-1

2nd integer= x

3rd integer= x+1

(x-1)(x) = 11(x+1)-22

x^2-x = 11x+11-22

simplify to: x^2-12x+11=0

factor to: (x-11)(x-1)

x=11, 1

1 doesn’t work because that would make the 1st integer equal to 0, and 0 isn’t a positive integer. So the three integers are 10, 11, and 12.

v=1788.75

step-by-step explanation:

i belive that is the answer

the answer for this is 0.25 km. : )