Part A: Marguerite rented a truck at $125 for 2 days. If she rents the same truck for 5 days, she has to pay a total rent of $275. Write an equation in the standard form to represent the total rent (y) that Marguerite has to pay for renting the truck for x days. (4 points)

Part B: Write the equation obtained in Part A using function notation. (2 points)

Part C: Describe the steps to graph the equation obtained above on the coordinate axes. Mention the labels on the axes and the intervals. (4 points)

will give 25 points and brinly p. s name parts

Think in terms of a linear function whose graph (a straight line) goes thru the 2 points given:

(2 days, $125) and (5 days, $275 ).

Find the equation of this line.

$275-$125 $150

The slope is m = = = $50/day

5 days - 2 days 3 days

Use the slope-intercept form of the equation of a str. line next:

y=mx + b becomes $275 = ($50/day)(5 days) + b.

Solving for b: $275 - $250 = b = $25

Thus, the equation of this line is y = ($50/day)x + $25, where that $25 is the upfront charge (y-intercept).

We must change this into standard form. To do this, group all the terms on one side. I choose to do that on the right side, so that the x term will be + .

($50/day)x - 1y + $25 = 0 is the equation of this line in std. form.

Part B: writing this equation in function notation:

y = ($50/day)x + $25 becomes f(x) = ($50/day)x + $25

Part C: To graph this equation, plot the two points on the graph:

(2, $125) and (5, $275) ... and draw a straight line thru them.

Alternatively, let x = 0 in f(x) = ($50/day)x + $25 to find the y-intercept; it is (0, $25).

Next, let f(x) = y = 0 = ($50/day)x + $25 to find the x-intercept:

-$25

50x + 25 = 0 => x = = (-1/2) day

$50/day

The x-intercept is ([-1/2] day, $0).

Of course, x must be zero or greater, as a negative number of days would be meaningless.

Step-by-step explanation: