Given: AE= 7 5/8cm, AB=BC, CD= 1/2cm, and DE is 3/8 more than AB. What is the length of DE?

Length of DE = 2.90 (Approx)

Step-by-step explanation:

Given:

AE = 7cm = 61 / 8 cm = 7.625 cm

AB = BC

CD = 1/2 cm = 0.5 cm

DE is 3/8 more than AB

Find:

Length of DE

Computation:

Assume;

AB = BC = x

So,

DE = x + 3/8(x) = [11 / 8]x = [1.375]x cm

AE = AB + BC + CD + DE

7.625 = x + x + 0.5 + [1.375]x

7.125 = 3.375 x

x = 2.1111 (Approx)

Length of DE = [1.375][2.111]

Length of DE = 2.90 (Approx)

28

step-by-step explanation:

8+8+6+6

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.