Twenty percent of all telephones of a certain type are submitted for service while under warranty. Of these, 60% can be repaired, whereas the other 40% must be replaced with new units. If a company purchases ten of these telephones, what is the probability that exactly three will end up being replaced under warranty

the probability that exact three would be replaced under each warranty is 0.34

Step-by-step explanation:

The computation of the probability that exact three would be replaced under each warranty is as follows

Given that

Submitted under warranty = P = 20%

Replaced with the new units = 40%

So replaced and submitted would be

= 40% × 20%

= 80%

Now let us assume the number of telephones be x for ending up for replacement

Total number of telephones purchased is 10

Now the probability by applying the formula of binomial probability is

= 0.34

Hence, the probability that exact three would be replaced under each warranty is 0.34

constant of proportionality = 3 and the equation is c = 3p.

step-by-step explanation:

c = kp   where c = amount of caffeine in mg., p = oz of pepsi and k is the constant of proportionality.

substituting the values given:

24 = 8k

k = 3.

the same value of k will be obtained if we substitute the other given values.