A chess club has 480 members but is losing 30 members each year. A computer club has 130 members and is gaining 20 members per year. When will the two clubs have the same number of members?

The two clubs will have the same number of members after 7 years

Step-by-step explanation:

Let the number of years is x

∵ A chess club has 480 members but is losing 30 members each year

∵ The number of years = x

∴ The total members after x years = 480 - 30x ⇒ (1)

∵ A computer club has 130 members and is gaining 20 members per year

∵ The number of years = x

∴ The total members after x years = 130 + 20x ⇒ (2)

∵ The two clubs will have the same number of members after x years

→ Equate (1) and (2)

∴ 480 - 30x = 130 + 20x

→ Add 30x t both sides

∵ 480 - 30x + 30x = 130 + 20x + 30x

∴ 480 = 130 + 50x

→ Subtract 130 from both sides

∵ 480 - 130 = 130 - 130 + 50x

∴ 350 = 50x

→ Divide both sides by 50

∴ 7 = x

∴ The two clubs will have the same number of members after 7 years

take the top number and divide it by a the bottom number

step-by-step explanation:

1/2 1 divied by 2 = .5

the answer is 24

step-by-step explanation: