The teacher asked 4 students to measure 4 different objects. Here are the results Which student had the greatest percent error?

Student 3 had the greatest percentage error.

Step-by-step explanation:

Student 1

Actual length = 50in

Measured length = 49in

Error = 50 - 49 = 1

Error% = 1/50 × 100

= 1 × 2

= 2%

Student 2

Actual length = 100cm

Measured length = 110cm

Error = 100 - 110 = 10

Error% = 10/100 × 100

= 10 × 1

= 10%

Student 3

Actual length = 2cm

Measured length = 2.5cm

Error = 2 - 2.5 = 0.5

Error% = 0.5/2 × 100

= 0.5 × 50

= 25%

Student 4

Actual length = 10ft

Measured length = 9½ft

Error = 10 - 9½ = ½

Error% = ½/10 × 100

= ½ × 10

= 1 × 5

= 5%

#teamtrees#WAP

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet