Household incomes in a certain region are skewed right with mean $57,550 and standard deviation $16,200. The probability that the mean of a random sample of 4400 household incomes would differ from the population mean by $500 or more is about:. (a) 0.12 (b) 0.09 (c) 0.04 (d) 0.21 (e) 0.18

6.5

step-by-step explanation:

you said it was in the question

~courtney

this is false ^.^ lol

idk

step-by-step explanation:

payback

step-by-step explanation:

for exempl this   system of equations   y = x - 3

                                                                y = 2x - 5

look   the line : y = x -3     ( red)

                            the line : y = 2x -5 ( bleus)