You are planning a party. The space restriction is such that you can only invite 4 people. There are 9 friends to choose from. In how many ways can you select those 4 people? a. There are (9-8+7+6(4+3+2+1) many ways.
b. There are (9-4)*(8-3)*(7-2)*(6-1) many ways.
c. There are 9*8*7*6 many ways.
d. There are 9*8*7*6/4*4*3*2*1) many ways.

Given:

Total number of friends = 9

Number of friend to invite = 4

To find:

The number of ways.

Solution:

We know that, total number of ways to select r items from n items is

So, the total number of ways to select 4 people from 9 friends is

Therefore, the required number of ways is .

Note: All options are incorrect.

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~

-8/2y-8=5/y+4-7y+8/y^2-16

we move all terms to the left:

-8/2y-8-(5/y+4-7y+8/y^2-16)=0

we can not solve this equation