A plane flies at 350 mph in the direction N 40° E with a wind blowing at 40 mph in the direction S 70° E. What is the plane’s drift angle?

The drift angle is approximately 7.65° towards the East from the plane's heading

Step-by-step explanation:

The speed of the plane = 350 mph

The direction in which the plane flies N 40° E = 50° counterclockwise from the eastern direction

The speed of the wind = 40 mph

The direction of the wind = S 70° E = 20° clockwise from the eastern direction

The component velocities of the plane are;

= (350 × cos 50)·i + (350 × sin 50)·j

= (40 + cos 20)·i - (40 × sin 40)·j

The resultant speed of the plane = + = 265.915·i +242.404·j

The direction the plane is heading = tan⁻¹(242.404/265.915) ≈ 42.35°

Therefore, the drift angle = Actual Angle - Direction of the plane = 50 - 42.35 ≈ 7.65° towards the East

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11