A pile of pebbles has a weight of 95 kg. Some of the pebbles put into a small bag.
The rest of the pebbles is put into a large bag.
The pebbles in the large bag weighs 45 kg more than the pebbles in the small
What is the weight of the pebbles in the large bag?

70kg

Step-by-step explanation:

s = small bag

b = big bag

Equations

s + b = 95

s + 45 = b

plug in

s + s + 45 = 95

2s + 45 = 95

2s = 50

s = 25

plug in to find big bag

25 + 45 = b

70 = b

The weight of the pebbles in the large bag is 70kg.

Step-by-step explanation:

This looks like a substitution algebra problem. To do this, I’m going to mark the large bag with (L) and the small bag with the variable, (s). I will make first 2 equations to show the value. The first equation would be L=45+s. The second equation would be 95=L+s. Since L is literally 45+s, add this into the 2nd equation. This would be 95=45+s+s. You should have 95= 45+2s and you would subtract 45 from both sides then. Finally, divide 2s by 2 to get what the small bag weighs, (which is 25kg). To find the large bag’s weight, use the first equation to find the answer. L= 45+s or 25. The answer would bring us to 70 kg.

i would need to see the dot plot : )