What is the area of a rectangle that has a height of 7x^2 and a width of 3x^2+8x+7

21x^4 + 8x + 7

Step-by-step explanation:

This is the answer because:

1) Simplify each term and multiply like terms and multiply them because in order to find the area we have to multiply the height and width.

2) Since we have to multiply like terms, 7x^2 and 3x^2 are the only like terms. Therefore, we multiply 7x^2 * 3x^2 = 21x^4.

3) The rest of the numbers are not like terms.

4) Therefore, the answer is 21x^4 + 8x + 7

Hope this helps!

false

step-by-step explanation:

false.   two legs of the trapezoid would be congruent, but the other two would not.   were all the legs congruent, then we'd have a square; were the 2 shorter sides congruent and the 2 longer sides also congruent, we'd have a rectangle.