A 6000-seat theater has tickets for sale at $26 and $40. How many tickets should be sold at each price for a sellout performance to generate a total revenue of $185,400?

x = number of tickets sold for $26 = 3900 tickets

y = number of tickets sold for $40 = 2100 tickets

Step-by-step explanation:

A 6000-seat theater has tickets for sale at $26 and $40. How many tickets should be sold at each price for a sellout performance to generate a total revenue of $185,400?

Let

x = number of tickets sold for $26

y = number of tickets sold for $40

x + y = 6000

x = 6000 - y

$26 × x + $40 × y= $185, 400

26x + 40y = 185400

Substitute

26(6000 - y) + 40y = 185400

156000 - 26y + 40y = 185400

Collect like terms

- 26y + 40y = 185400 - 156000

14y = 29400

y = 29400/14

y = 2100 tickets

x = 6000 - y

x = 6000 - 2100

x = 3900 tickets

Hence

x = number of tickets sold for $26 = 3900 tickets

y = number of tickets sold for $40 = 2100 tickets

step-by-step explanation:

answer: expected value of x = 1.0

step-by-step explanation:

p(x=0) = 0.25

p(x=1) = 0.50

p(x=2) = 0.25

expected value for x = 0×0.25 + 1×0.5 + 2×0.25 = 1.0