Consider the field F = (x, y,z) and the cone z 2=x2+y2/a2- a. Show that when a = 1, the outward flux across the cone is zero. b. Find the outward flux (away from the z-axis), for any a>0. Therefore, the flux is zero. Interpret this result. A. The fluxes for x > 0 and x < 0 balance when a = 1, so the flux is zero. B. The field is parallel to the surface at every point, so the flux is zero. C. The fluxes for y > 0 and y < 0 balance when a-1, so the flux is zero. D. The field is normal to the surface at every point, so the flux is zero.

I've been working on this for a few days and i just don't understand, it's due in a few hours. you. the direction of a vector is defined as the angle of the vector in relation to a horizontal line. as a standard, this angle is measured counterclockwise from the positive x-axis. the direction or angle of v in the diagram is α. part a: how can you use trigonometric ratios to calculate the direction α of a general vector v = < x, y> similar to the diagram? part b suppose that vector v lies in quadrant ii, quadrant iii, or quadrant iv. how can you use trigonometric ratios to calculate the direction (i. e., angle) of the vector in each of these quadrants with respect to the positive x-axis? the angle between the vector and the positive x-axis will be greater than 90 degrees in each case. part c now try a numerical problem. what is the direction of the vector w = < -1, 6 > ?