What is the area of the region bounded by the graph of the equation x^2+y^2 + 3 = -4y + 6x-1?

9π

Step-by-step explanation:

What we need  to do here is convert this equation into a standard circle equation;

x^2+y^2 + 3 = -4y + 6x-1,

x^2+y^2+4y-6x+1 = 0,

x^2-6x+(-3)^2 + y^2+4y+(2)^2  = 3^2

(x-3)^2 + (y+2)^2 = 3^2,

so we have a circle with a radius of 3, and hence the area of our region is π(3)^2 = 9π. correct!

27

step-by-step explanation:

on a coordinate grid, point a is at (−4.0, −2.4) and point b is at (4.0, −2.4). point b is a reflection of point a across the –axis. input either a lowercase x or i think is the right awnser

step-by-step explanation: