Hey hope someone can figure this out hopefully it's not that hard. A chocolate box has the shape of a prism with a base that is a
rhombus. Each side length of the rhombus is 3.6 cm.
The angles between adjacent sides of the base are 60° and 120°.
The prism is 10.8 cm long.

a) Draw a net for this box.
b) How is your net different from the cardboard net from
which the box is made? Explain.

Part (a)

See the diagram below for the net for this box. We have two rhombuses that are the two bases of the rhombic prism. The six rectangles form the lateral sides.

In geometry, a net is effectively the outer surface of a 3D object, but it has been laid flat on a plane. Think of unwrapping a present without throwing any pieces away. The net would be the wrapping laid out flat. As another example, a net of a cardboard box would be laying the box flat. So you're unfolding the box. This is mentioned in part (b).

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Part (b)

The main difference from this net compared to a net for a cardboard box is that everything is a rectangle for a cardboard box. This is because a cardboard box folds up into a rectangular prism.

So in the diagram below, you'll replace each rhombus with a rectangle. You'll make all four angles 90 degrees.

hello from mrbilldoesmath!

answer:   x^2 + y^2 = 1024

discussion:

the equation of a circle with center (h,k) and radius "r" is

(x-h)^2 + (y-k)^2 = r^2.

in our case

(x-0)^2 + (y-0) ^2 = 32^2 = 1024

you,

mrb