Consider RS endpoints R(-2,1) and S(4,4) Find point Q that is 2/3 away NEED THIS ASAP PLEASE ANSWER

The question does not clearly specify from which endpoint Q is at 2/3. I'll assume Q is 2/3 away from R.

The point Q is (2,3)

Step-by-step explanation:

Take the aligned points R(-2,1), S(4,4), and Q(x,y) in such a way that Q is 2/3 away from R (assumed).

The required point Q must satisfy the relation:

d(RQ) = 2/3 d(RS)

Where d is the distance between two points.

The horizontal and vertical axes also satisfy the same relation:

x(RQ) = 2/3 x(RS)

And, similarly:

Working on the first condition:

Removing the parentheses:

Adding 2:

x = 2

Similarly, working with the vertical component:

Removing the parentheses:

Subtracting 1:

y = 3

The point Q is (2,3)

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3