What are the first three of a sequenced the nth term is -7n-1

1st term = a(1) = -7(1)-1 = -7-1 = -8

2nd term = a(2) = -7(2)-1 = -14-1 = -15

3rd term = a(3) = -7(3)-1 = -21-1 = -22

term would be -8, -15, -22

the correct answer is 5 6 and 7

n=9

step-by-step explanation:

7 times a number = 7n

decreased by 13 = 7n-13

same as is =

5 times the number = 5n

increased by 5 = 5n+5

7n-13 = 5n+5

2n=18

n=9