Mathematics, 25.11.2020 19:50, cornpops1749

Derive the equation of the parabola with a focus at (2, −1) and a directrix of y = −1/2. A. f(x) = −(x + 2)2 − 3/4
B. f(x) = (x + 2)2 + 3/4
C. f(x) = −(x − 2)2 + 3/4
D. f(x) = −(x − 2)2 − 3/4

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Derive the equation of the parabola with a focus at (2, −1) and a directrix of y = −1/2. A. f(x) = −(x + 2)2 − 3/4 B. f(x) = (x + 2)2 + 3/4 C. f(x) = −(x − 2)2 + 3/4 D. f(x) = −(x − 2)2 − 3/4

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Derive the equation of the parabola with a focus at (2, −1) and a directrix of y = −1/2. A. f(x) = −(x + 2)2 − 3/4
B. f(x) = (x + 2)2 + 3/4
C. f(x) = −(x − 2)2 + 3/4
D. f(x) = −(x − 2)2 − 3/4