A shipping company claims that 90% of its packages are delivered on time. Jenny noticed that out of the last 10 packages shipped, 2 were late. What is the probability that 2 out of 10 randomly selected shipments would be late?

The probability is;

0.0000003645

Step-by-step explanation:

The probability of packages being early p is 90% = 0.9

The probability of packages being late q will be 1-p = 1-0.9 = 0.1

So the probability of 2 out of 10 random late will be subject to Bernoulli approximation of the Binomial theorem

That will be;

P(X = 2) = 10 C 2 0.9^2 0.1^8

= 0.0000003645

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step-by-step explanation:

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0