What are the values of a, b, and c in the quadratic equation –2x2 + 4x – 3 = 0?

the value of constants are a = - 2, b = 4 and c = -3

Step-by-step explanation:

The general quadratic equation is q(x) = ax² + bx + c where a,b and c are constant and a ≠0

The given quadratic equation is -2x² + 4x - 3

To obtain the values of a, b and c by compare the general equation with -2x² + 4x - 3

now compare the ax² + bx + c with -2x² + 4x - 3

so, values are  a = - 2, b = 4 and c = -3

Therefore, the value of constants are a = - 2, b = 4 and c = -3

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation: