a long steel beam has a length of twenty-five meters on a cold day when the temperature is 0*c. what is the length of the beam on a hot day when t

Complete question is;

A long steel beam has a length of twenty-five meters on a coldday when the temperature is 0°C. What is the length of the beam on a hot day when T = 40°C. (α_steel = 1.1 × 10^(-5) °/C)

a. 25.00044 m

b. 25.0044 m

c. 25.011 m

d. 25.044m

e. 25.11 m

Option C: 25.011 m

Step-by-step explanation:

We are given;

Initial Temperature; T1 = 0°C

Final Temperature; T2 = 40°C

Coefficient of linear expansion of steel; α_steel = 1.1 × 10^(-5) °/C

Initial length; L_o = 25 m

We know that formula for change in length is;

ΔL = LαΔT

Plugging in the relevant values, we have;

ΔL = 25 × 1.1 × 10^(-5) × (40 - 0)

ΔL = 0.011 m

Thus, new length is;

L1 = L_o + ΔL

L1 = 25 + 0.011

L1 = 25.011

81 seats

step-by-step explanation:

if you multiply 0.65 times 125 then you get 81.5 seats. well since you can't have half of a seat you have to round down and get 81 seats in the no children zones. that leave 44 seats outside of the no children zone.

correct choice is b

step-by-step explanation:

when you calculate the average rate of change of a function, you are finding the slope of the secant line between the two points. for the function the average rate of change from point to point can be calculated as

to find the average rate of change from day 2 to day 10, note that at day 2, 8 houses were sold, so a(2,8) and at day 10, 2 houses were sold, so b(10,2). thus,