Reasoning Graph the set of ordered pairs (0, 2). (1.4), (2,6). (3.8). Determine whether the relationship is a linear function Explain how you know.

No, it does not. See below.

Step-by-step explanation:

Lets find out the linear equation that passes trough (-2, 0) and (0, -6).

We know every linear equation has the form: y = mx + b

Where m is the slope on the curve and b the independent term.

We know that, given 2 points (x1,y1) and (x2,y2) we can find the slope m as:

m = (y2-y1)/(x2-x1)

In our case lets replace (x1,y1) and (x2,y2) by (-2, 0) and (0, -6) (notice it could be done in the inverse sense where (-2, 0) is (x2,y2) and (0, -6) is (x1,y1) ). So, our slope is:

m = [-6 - 0] / [0 - (-2)]

m = -6/2 = -3

So, we have a downward linear function with slope -3, this is:

y =  -3x + b

Now, for finding b just replace any of the 2 points given in the equation. Lets replace (-2, 0):

0 = -3(-2) + b

0 = 6 + b

Subtracting 6 in both sides:

-6 = b

So, our independent term is -6 and the function is:

y = -3x - 6

Now lets see if this linear eqution passes trough (2,6). If it does, we can replace the values on the equation. Replacing x by 2:

y = -3(2) - 6 = = -6 - 6 = - 12

So, in our equation, we x is 2 y is -12, and not 6 as in the point (2,6). So, our equation does not passes trough (2,6)

spinning a 1, 2, or 3. option d.

step-by-step explanation: when spinning a number graph up to 4, and aiming for any number less than 3, that automatically eliminates the number 4. now you have two numbers to spin on that are less than 3, but the number 3 is included in this question because it's no greater of an number than itself. i hope this you : )

hreryryrranswer:

step-by-step explanation: