Find the perimeter of the polygon ABCD that has its vertices at A(2, –2), B(6, –2), C(6, 6), and D(2, 6). A)

12 units

B)

64 units

C)

32 units

D)

24 units

D. 24 Units

Step-by-step explanation:

tracing the points given we get a rectangle

the perimeter of a rectangle = 2a+2b

a=length

b= width

in this case a= 8

b= 4

the perimeter of a rectangle = (2*8)+(2*4)

the perimeter of a rectangle = 16+8

the perimeter of a rectangle = 24

step-by-step explanation:

ok so im not 100% sure but you would start by adding 5.1t and 1.9t beacuse they have the same variable. that is 7t.   then add -3.6 + 1.2 which is -2.4

so then keep that as -2.4 + 7t. i apologize if this is incorrect. best luck on your test < 3

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)