What is the equation of the line parallel to 8x−16y=−14 and passing through (3,0)? 6x−12y=18
6x+12y=18
12x−6y=−18
12x+6y=18

2y = x - 3

Step-by-step explanation:

Parallel lines can be defined as lines that do not intersect and as a result of this, parallel lines have the same slope but different intercepts.

Given the following data;

Points (x, y) = (3, 0)

Equation is 8x - 16y = -14

To find the equation of the line?

First of all, we would have to determine the slope of the line;

y = mx + c equation 1

8x - 16y = -14

Rearranging the equation, we have

16y = 8x + 14

Dividing through by 16, we have;

y = 8/16(x) + 14/16

y = 1/2(x) + 7/8

Therefore, the slope, m is 1/2

*To find the intercept*

Since the line is parallel we would use, m = 1/2

Substituting the values into equation 1, we have;

y = mx + c for x = 3 and y = 0

0 = 1/2(3) + c

c = -3/2

Re-writing the equation of line;

Slope, m = 1/2

Intercept, c = -3/2

y = 1/2(x) + (-3/2)

Multiplying all through by the lowest common denominator "2"

2y = x - 3

domain is all the x values included in the

0 ≤ x ≤ 2

range is all the y values of the graph

-2 ≤ y ≤ 2

***keep in mind that there are different ways to show domain and range

hope this !

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step-by-step explanation: