John draws AABD, with CD as the perpendicular bisector of AB such that AACD and ABCD are congruent to each other. DO
Which statement can John use this figure to prove?
Every isosceles triangle is a right triangle.
The base angles of any triangle are congruent.
The points on the perpendicular bisector of a side of a triangle are equidistant from all of the vertices of the triangle.
The points on the perpendicular bisector of a side of a triangle are equidistant from the vertices of the side it bisects.

The statement that John can use the figure given to prove is that: D. The points on the perpendicular bisector (CD) of a side (AB) of a triangle (triangle ADB) are equidistant from the vertices (<A and <B) of the side it bisects.

Recall:

From the triangle in the image drawn by John, it means that since CD a perpendicular bisector of side AB, it means that the distance from point D to vertex A and the distance from point D to vertex B are equal.

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The points on the perpendicular bisector of a side of a triangle are equidistant from the vertices of the side it bisects.

Step-by-step explanation:

It is the last option. The perpendicular bisector theorem states that if  a point lies on  the bisector of a segment it is equidistant from the endpoints.

Meaning

If a perpendicular bisector is a line of the side of the triangle , it bisects the sides forming two right angles .

The first three choices are incorrect because

1) the figure shows a triangle bisected into two triangles and option 1 tells about 1 isosceles triangle.

2) The base angles of any triangle can be different or same .

3) the three perpendicular bisectors meet at a point called the circumeter. We have 1 perpendicual bisector which is dividing the triangle into two equal triangles.

squares, rhombus, rectangles

you would have to sell 24 bracelets.

step-by-step explanation:

84/3.5 = 24