A truck can be rented from Company A for $130 a day plus 50.30 per mile. Company B charges 570 a day plus 50.70 per mile to rent the same truck. Find the number of miles in a day at which the rental costs for Company A and Company B are the same.

Not possible

Step-by-step explanation:

You use the formula y = mx + b to make equations for both situations then solve from there

Let x be miles driven

Company A:

y = 50.30x + 130

Company B:

y = 50.70x + 570

You solve by making the equations equal each other to figure out the variable (miles driven)

50.70x + 570 = 50.30x + 130

50.70x + 570 - 50.30x + 130 - 50.30x

0.4x + 570 - 570 = 130 - 570

0.4x = -440

x = -1100

Therefore there is no amount of miles you can drive for Company A and Company B to have the same rental costs

i agree because i see the other persons thinking is clear

18 units²

step-by-step explanation:

first let's find altitude bd using the distance formula

d = √((y₂ - y₁)² + (x₂ - x₁)²)

bd = √((0 - -3)² + (0 - 3)²)

bd = √18

given the placement of points a and c, we can denote that point d bisects segment ac.

we will call ac the base.

using the distance formula

ac = √((0 - 6)² + (-6 - 0)²)

ac = √72

knowing our base and our height, we can plug these into our triangle area formula

area = (b * h)/2

area = (√18 * √72) / 2

area = (√1296) / 2

area = 36 / 2

area = 18 units²