I need help with my project. I’m stumped :/ The Ferris wheel I’ve chosen is the high roller Ferris wheel in Las Vegas.

This is what I know:

Height-550ft
Radius-260ft
Midpoint-290ft
Height from the ground: 30ft
Full rotation: 30 min
Increments: 28

Sin equation:
y=260sin(π/15x) + 290

These are my questions:
I need help with the fourth bullet point in part 1 and the second equation (shadow being cast on the ground) in part 2. (I’m pretty sure my sin function is the first equation.

And then the 3rd paragraph of part 2.

Contact me if you need more information or want to keep in touch :)
Instagram:h3ctrb
Snap:just. hectorb

The deadline line is 12/4

I’ll give more points

How to do this , and can some one explain

Acar started driving from city a to city b, distance between which is 620 miles, at a rate of 60 mph. two hours later a truck left city b and started moving towards city a at a rate of 40 mph. what distance from city a is the point where the truck and the car will meet?

Asystem of linear equations with more equations than unknowns is sometimes called an overdetermined system. can such a system be consistent? illustrate your answer with a specific system of three equations in two unknowns. choose the correct answer below. a. yes, overdetermined systems can be consistent. for example, the system of equations below is consistent because it has the solution nothing. (type an ordered pair.) x 1 equals 2 comma x 2 equals 4 comma x 1 plus x 2 equals 6 b. no, overdetermined systems cannot be consistent because there are fewer free variables than equations. for example, the system of equations below has no solution. x 1 equals 2 comma x 2 equals 4 comma x 1 plus x 2 equals 12 c. yes, overdetermined systems can be consistent. for example, the system of equations below is consistent because it has the solution nothing. (type an ordered pair.) x 1 equals 2 comma x 2 equals 4 comma x 1 plus x 2 equals 8 d. no, overdetermined systems cannot be consistent because there are no free variables. for example, the system of equations below has no solution. x 1 equals 2 comma x 2 equals 4 comma x 1 plus x 2 equals 24