The general form of an parabola is 4y2+40y+3x+103=0. What is the standard form of the parabola?

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  x = -4/3y² -40/3y -103/3

  x = -4/3(y +5)² -1

Step-by-step explanation:

Solve for x.

  x = (4y² +40y +103)/(-3)

  x = -4/3y² -40/3y -103/3 . . . . 'standard form' in the US

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Taking our clues from the graph*, we can write the vertex form equation as ...

  x = -4/3(y +5)² -1 . . . . . . 'standard form' in other places

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* The vertex is (-1, -5), so for some leading coefficient, the equation will be ...

  x = a(y -(-5))² +(-1) = a(y +5)² -1

The value of 'a' is the scale factor. Here, that is the difference between the parabola value (x = -2 1/3) and the vertex value (x = -1) one unit away from the vertex.

the difference between a number and 5 is -2.

step-by-step explanation:

notice that the equation you are given has -2 (negative 2) on the right side, not 2. when you subtract 5 from a number n, you are finding the difference between the number and 5.

the difference between a number and 5 is -2.

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step-by-step explanation:

sorry no step by step