The perimeter of a rectangle is 208 inches. The ratio of its length to its width is 5:3. What are the

dimensions of this rectangle?

A. 60 in by 44 in

B. 65 in by 39 in

C. 68 in by 36 in

D. 72 in by 32 in

65 in and 39 in respectively

Step-by-step explanation:

Let r be the common ratio; when we multiply both L and R by this common ratio, we'll get the actual length and actual width of the rectangle,  Recalling that the formula for the perimeter of a rectangle is P = 2L + 2R, we get:

2(5r) + 2(3r) = 16r = 208 in

Then r = 208/16 = 13

Thus, the actual length is 5(13 in) and the actual width is 3(13 in.),

or 65 in and 39 in respectively.

As a check, calculate 65 in / 39 in; this comes out to 5:3, as required.

Then

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°