Mathematics, 21.11.2020 15:20, haza1873

Per quale valore di k appartenente a R una retta del fascio di equazione (k – 1)x – (3 – 3k)y + 2k – 3 = 0 è parallela alla bisettrice del primo e terzo quadrante?
A)k=1
B)k= -1
C) per ogniK appartenente aR
D)non esiste k appartenente a R
la risposta e una di queste ma non so risolverlo

Answers: 2

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Per quale valore di k appartenente a R una retta del fascio di equazione (k – 1)x – (3 – 3k)y + 2k –...