I really need help on 2 !!

x=2

y=-1

z=3

Step-by-step explanation:

X = 7+2y-z

3(7+2y-z)+y-z=2

21+6y-3z+y-z=2

21+7y-4z=2

7y-4z=-19 (subtract both side by 21)

2(7+2y-z)+3y+2z=7

14+4y-2z+3y+2z=7

14+7y=7

7y=-7 (subtract both side by 14)

y=-1 (divide both side by 7)

{7y-4z=-19

{y=-1

7.-1 - 4z=-19

-7-4z=-19

-4z=-12

Z=3

x=7+2y-z (y=-1 z=3)

x=7+2.-1 - 3

x=7-2-3

x=2

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

step-by-step explanation:

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