The midpoint of AB is M ( 1 , − 3 ). If the coordinates of A A are ( − 6 , − 7 ),what are the coordinates of B?

a= -4

b=1

Step-by-step explanation:

Midpoint=(1,-3)=(x,y)

A=(-6,-7)=(x1,y1)

Let ,the coordinates of B be 'a and b' .

So,

B=(a,b)=(x2,y2)

Using ,midpoint formula,

(x,y)=(x1+x2\2 , y1+y2 \2)

or, (1,-3)=(-6+a\2 , -7+b \2)

Now,

Taking the corresponding sides,

or, 1 =-6+a/2

or, 1*2=6+a

or, 2=6+a

or, 2-6=a

a=-4

Then,

-3= -7+b/2

or, -3*2= -7+b

or, -6 =-7+b

or, -6+7=b

b=1

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

i would say b) is your answer

sorry if im wrong

step-by-step explanation: