Please help me solve this?

12y√3x

Step-by-step explanation:

2√108y²

so you will need two of something to take one out from under the squareroot

we can rewrite so we can take a out

we can rewrite y² as y*y so we can take a y out

we can rewrite as so we can take a out

for 108 think what is the smallest prime number that divides 108 and is 2

108= 2*54

same algorithm, smallest prime number that divides 54 is 2 so

108=2*2*27

same algorithm, smallest prime number that divides 27 is 3 so

108=2*2*3*9

we know 9 is 3*3 so

108=2*2*3*3*3 we can take out one 2 and one 3

put them all toghether now

2*2*3**y*√3x = 12y√3x

y - y1 = m(x- x1)

y - (-5) = 2/3(x -0)

y + 5 = 2/3x

y = 2/3x - 5