For those who are good with equations.(unlike me when it comes to this)

a = 5

Step-by-step explanation:

When the coefficients of the variables are equal with different constants, then you will get an equation which is never true.

For this particular equation, when a on the right side has a coefficient of 5, you will get the equation: 4(a - 2) + a = 5a - 4.

When you distribute the factors in the parenthesis and add the like terms of a together, 4(a - 2) + a will become 5a - 8. This is because 4(a - 2) + a = 4(a) + 4(-2) + a = 4a - 8 + a = 5a - 8.

Now when you simplify 5a - 8 = 5a - 4 by subtracting 5a from both sides, you will get an equation with unlike constants. For instance 1 = 0.

Now:

5a - 8 = 5a - 4

-5a -5a

-8 = -4

This is never true, so therefore, there is no solution.

you divide them and then you get the answer i took this class this year

step-by-step explanation:

answer:

given the linear inequality :

add 2y to both sides we get;

simplify:

add 12 to both sides of an equation;

simplify:

divide both sides by 2 we get;

or

the related equation for the inequality equation [1] is;

y-intercepts defined as the graph crosses the y-axis.

substitute x =0 in [2] to solve for y;

y = 6

x-intercepts defined as the graph crosses the x-axis.

substitute value y = 0 to solve for x;

subtract 6 from both sides we get

multiply both sides by 2 we get;

or

x = -12

now, plot these point (0, 6) and (-12, 0) on graph as shown below and shade the graph below the solid line.