A 40-foot ladder is leaning against a building that is 12-feet tall. What is the angle of elevation that the ladder makes with the ground? Round your answer to the nearest degree.

The angle of elevation is to the nearest degree

The right-angled triangle formed can be solved for the angle of elevation if we note that

So, the trigonometric ratio to be used here is the . That is

substituting the values

Now, to find the angle of elevation,

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θ = 17.45°

Step-by-step explanation:

Given that,

Length of a ladder = 40 foot

Height of a building = 12 feet

We need to find the angle of elevation that the ladder makes with the ground.

40 foot will be the hypotenuse and 12 feet will be the perpendicular distance.

Using trigonometry for this:

So, the angle of elevation that the ladder makes with the ground is 17.45°.

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

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