What is an equation in point slope form of the line that passes through the point (6,-2) and had a slope of 3

y - 6 = 3(x + 2)

Step-by-step explanation:

Point-slope form: y - y1 = m(x - x1)

Given: m(slope) = 3, (6, -2)

(x1, y1) = (6, -2)

Input the given values of the slope and the point into the equation for point-slope form:

y - (-2) = 3(x - 6)

y + 2 = 3(x - 6)

The equation written in point-slope form is: y + 2 = 3(x - 6)

it could 14.28 but if its not that one then it has to be the 17 one. hope this ! : )

step-by-step explanation:

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.