Paul draws △ABC and the medians from vertices A and B. He finds that the medians intersect at a point and he labels this point X. Paul claims that point X lies outside △ABC. Do you think this is possible? Complete the explanation.

The answer is "Through which we can infer that perhaps the ABC triangles is obstinate shaped".

Step-by-step explanation:

Paul draws that ABC as well as the Median triangle from and A and B nodes. If the median passes after a certain point, and his marks the point X. Paul now says point X (i.e., a triangle's center) is outside the ABC triangle.  

They may also conclude that perhaps the ABC triangle does have an obtuse angle because the centroid is in the ring in case of even a severe triangle, that centroid is already on the right triangle in case of the triangle and cases of an obtuse-angled rectangle, the angular velocity is an outside ring.

there will be 35 boys in each team. : )

it is 10.6 according to my calculations