Pentagon ABCDE and pentagon A'B'C'D'E' are shown on the coordinate plane below: Pentagon ABCDE and pentagon A prime B prime C prime D prime E prime on the coordinate plane with ordered pairs at A negative 4, 5, at B negative 6, 4, at C negative 5, 1, at D negative 2, 2, at E negative 2, 4, at A prime 4, negative 7, at B prime 2, negative 6, at C prime 3, negative 3, at D prime 6, negative 4, at E prime 6, negative 6. Which two transformations are applied to pentagon ABCDE to create A'B'C'D'E'?

the polynomial is a perfect square trinomial of the form a^2-2ab+b^2:

option a. true

step-by-step explanation:

9x^2-12x+4

comparing with the form a^2-2ab+b^2

1.) a^2=9x^2

solving for a: square root both sides of the equation:

sqrt(a^2)=sqrt(9x^2)

a=sqrt(9) sqrt(x^2)

a=3x

2.) b^2=4

solving for b: square root both sides of the equation:

sqrt(b^2)=sqrt(4)

b=2

to be a perfet square trinomial 2ab must be equal to 12x. let's check:

2ab = 2 (3x) (2)

2ab = 12x

correct

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hello there!

i believe the answer is

(cot2+1)/sec2=cot2

    csc2/sec2=cot2

  (1/sin2)/(1/cos2)=cot2

  (1/sin2)(cos2/1)=cot2

  cos2/sin2=cot2

  (1/tan2)=cot2

  (cot2)=(cot2)

hope this !

hyperz ^_^