Out of 85 adults selected randomly from one town, 63 have health insurance. Find a 90% confidence interval for the true proportion of all adults in the town who have health insurance. a) find sample proportion P with hat on top.

b) use z subscript alpha divided by 2 end subscript equals 1.645 space spaceto find margin of Error for 90% confidence interval.

c) Find the confidence interval.

d) Interpret your interval

show work. round all numbers to at least 3 decimal places. you don't need to explain in words where you get the numbers(unless it is easier for you than writing in math notations). you can only write in math notations. it should be clear which function you are using.(normalcdf, invnorm. invt,..)