A 12-foot ladder is placed four feet from the base of a wall. How far up the wall will the ladder reach?

8sqrt 2 or sqrt 128

Step-by-step explanation:

We can use the Pythagorean Theorem. Since the ladder is leaning against the wall, it is the hypotenuse. It is also 4 feet away from the wall so 12^2-4^2=b^2 b^2=128 so b=8sqrt 2 or sqrt 128.

answer: bearing in mind that a rectangle has a perimeter of length + length + width + width.

step-by-step explanation:

p = perimeter

l = length

x=width

p = 2l + 2x

p = 2(l+x)     < ==== perimeter of the base of the box.