Given P(x) = a(b-x)(x+c)(dx + 4), where a, b, c and d are constants. Given the first term of the expansion of P(x) is –12x³ and has a zero of -3. Find P(x) if the
polynomial leaves a remainder of 48 when divided by x and a remainder of
- 312x +312 when divided by
4x -x²-3.

really need help.. please

it is contrapositive

i could not see the question too well so check yourself again too . this is because i want you to get it correct.

y -5 = (-1/4)(x + 8)

step-by-step explanation:

hello from mrbilldoesmath!

answer:   x (x+6)^2, choice b

discussion:

factor x out of the equation:

x^3 + 12x^2 + 36x = x (x^2 + 12x + 36).

note that 6+6 = 12 and 6*6 = 36 so the above factors into:

x (x+6)^2

which is choice b

you,

mrb