(8 - h)(jh + jh) use h=-1 and j=5

I would do this but im kind of confused please help

-90

Step-by-step explanation:

(8-h)(jh+jh)

Since the values of h and j are given, we use substitution to replace the variables with their number values

(8-(-1))(j(-1)+j(-1) replaced all the h with -1

(8-(-1))((5)(-1) + (5)(-1)) replaced all the j with 5

Then we solve inside the parenthesis first

(8+1)(-5+(-5))

(9)(-10)

Then, multiply

-90

pentagon

step-by-step explanation:

the coordinates   a(5, -2), b(3,-1),c(-4,-4) d(-3,8) and e(-1,4) forms the vertices of the polygon when they are connected in order.

in order to classify that which polygon is it with the given coordinates, first count the number of vertices and then count the number of sides it can make with these vertices.

since, the given coordinates have five vertices, therefore, it will make five sides. moreover, pentagon is regular in nature therefore it will be convex.

now, a polygon with five sides is known as pentagon, therefore, the given polygon is the pentagon.