An object is thrown upward from the top of a 200-ft cliff with a velocity of 12 feet per second. The height above ground, h, in feet of the object after t seconds is h = -16t2 + 12+ + 200. How long
after the object is thrown will it strike the ground? Round to the nearest tenth of a second.

16.9 times 2.85

step-by-step explanation:

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0

b. f(x) = –√x + 3this is the correct answer