A baseball is thrown into the air from the top of a 224-foot tall building. The baseball's approximate height over time can be represented by the quadratic equation h(t) = -16t2 + 80t + 224, where t represents the time in seconds that the baseball has been in the air and h(t) represents the baseball's height in feet. When factored, this equation is h(t) = -16(t - 7)(t + 2). What is a reasonable time for it to take the baseball to land on the ground?

A.
7 seconds
B.
5 seconds
C.
2 seconds
D.
9 seconds

C.  2 seconds

Step-by-step explanation:

given equation:  h(t) = -16(t - 7)(t + 2).

A h(7) = -16(7 - 7)(7 + 2) = 0 second

B h(5) = -16(5 - 7)(5 + 2) = -336 seconds

C h(2) = -16(2 - 7)(2 + 2) = 320 seconds

D h(9) = -16(9 - 7)(9 + 2) = -352 seconds

therefore, the only reasonable time for the ball the reach the ground is 320 seconds,

so the answer is C.  2 seconds

b. 1.25 hr

step-by-step explanation:

if you have a constant speed of 60 mph, then you have a ratio between 60 mi. to 1 hr. dividing both sides by 60 we get the ratio

1 mi. to

then mult. both sides by 75 we get the ratio

75 mi. to

simplifying we get

75 mi. to

or 1.25 hr.

0 and 5 minutes

step-by-step explanation:

given that one morning eight buses arrive late by the number of minutes given below:

0 8 2 6 9 2 0 7 8

write these in ascending order

0   0 2 6 7 8 8 9

in the afternoon two more buses arrive at the bus stop say by x and y minutes late.

total number of buses = 10

median = average of 4th and 5th after arranging in ascending order

since 4th entry is 6, the values of x and y should be below 6

also given 0 is the mode so either x or y or both should be 0 because then only 0 gets the maximum frequency and hence mode

thus we have

0 0 0 2 6 7 8 8 9 and another unknown entry which is below 6.

since median is 3.5, we have the unknown entry to be 5 only because then only median =( 2+5)/2

thus the after noon buses were late by 0 and 5 minutes.