What is an equation of the line that passes through the points (4,−1) and (8, 5)? Put your answer in fully reduced form. HELP PLS

y=2/3x-7

Step-by-step explanation:

The slope intercept formula is

y=mx+b

(m) is the slope (rate of change)

(b) is the y intercept (where the line crosses the y axis [vertical])

We need to find the slope and the y intercept. First we will find the slope.

The formula for slope is y1-y2/x1-x2

In and ordered pair the first value is the (x) and the second is the (y).

(x, y)

We take the (y) of one of the given points and subtract the (y) of the second given point, then divide it by the (x) of one of the given points and the (x) of the other given point.

5-(-1)/8-4

Simplify.

5-(-1) =5+1= 6

8-4=4

6/4 Simplify

3/2 is our slope.

Now we apply out new slope into our y=mx+b

y=3/2x+b

Now we need to find the (b) which is the y intercept.

To do this we need to use one of our given points, you can choose either but for this I'll use (4, -1).

In this ordered pair 4 is the (x) and -1 is the (y)

So replace (y) with -1 and (x) with 4

-1=3/2(4)+b

Now solve as usual.

-1=6+b

subtract 6 from each side

-7=b

b=-7

Put our (m) and (b) into our formula.

y=2/3x-7 is our equation.

i believe that the slope of the line is -5

step-by-step explanation: