Please helppp But please explain the answer, Bc I want to understand.

Which is an equation for a line that passes through (0,-3) and is perpendicular to the graph of the line y=2x-3?

1. Y=-2x+3
2. Y= -2x-3
3. Y=-1/2x +3
4. Y=-1/2x-3

I think the answer is 2

Step-by-step explanation:

I it is perpendicular to y=2x-3 then the x value has to be -1 meaning that the x value has to be -2x

so we have Y=-2x+c

We know the Y value is -3 from the co ordinates (0,-3)

so now we have -3=-2x+c

we also know x=0 from the co-ordinates (0,-3)

so we now have -3=-2*0+c

-3=0+c

to make the equation work c has to be -3 meaning that we now have

-3=0-3 which is

Y=-2x-3

341

step-by-step explanation:

all you have to do is 9x31 (which equals 279) and then 20x31 (which equals 620). then you have to subtract. 620-279=341.

complete the steps to find the area of the trapezoid.

area of rectangle = 256   square units

area of triangle 1 = 24  square units

area of triangle 2 = 16  square units

area of triangle 3 =   96 square units

area of trapezoid = 120  square units

step-by-step explanation: